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Old 10-16-2005, 01:47 AM   #1
mr_user
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Some late night pre-cal

Hey guys,

Just started my pre-cal class, and I missed the past week of school due to unforeseen matters. Anyways, I have a big test Monday and am stumped on something.

I understand that the domain of a function is any number that would make the function impossible to solve. For example, f(x)= 10-(x-4). The domain of the function would be all real numbers except for 6, as plugging 6 for an x value would make the function 0, or impossible. Now I don't understand the "range" of the function at all. I've read the book a number of times and still don't understand as it only states, "The y-values set". If anyone could enlighten me on the concept of the range of a function I would most greatly appreciate it!

Thanks a bunch!
Matt

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Old 10-16-2005, 07:32 AM   #2
RCHavok797
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Quote:
Originally Posted by mattfelner
Hey guys,

Just started my pre-cal class, and I missed the past week of school due to unforeseen matters. Anyways, I have a big test Monday and am stumped on something.

I understand that the domain of a function is any number that would make the function impossible to solve. For example, f(x)= 10-(x-4). The domain of the function would be all real numbers except for 6, as plugging 6 for an x value would make the function 0, or impossible. Now I don't understand the "range" of the function at all. I've read the book a number of times and still don't understand as it only states, "The y-values set". If anyone could enlighten me on the concept of the range of a function I would most greatly appreciate it!

Thanks a bunch!
Matt
The domain is the set of values for which the function is defined which means any set of numbers that make the function a true statement. The range is the limits of the values a function can take or more simply put what f(x) or y is for any x that makes the function a true statement. In your above example 6 does not make the function as you put it impossible to solve because the answer is not 0 but 8 which is f(x) or y. Even if the answer is 0 which happens when x is 14, 0 is a valid solution. Remember to do what is contained in the parenthesis first. For example when x is 6, 6-4 =2 and then 10-2=8. The domain of the above function is all real numbers and the range is all real numbers.
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Old 10-16-2005, 01:48 PM   #3
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Quote:
Originally Posted by mattfelner
Hey guys,

Just started my pre-cal class, and I missed the past week of school due to unforeseen matters. Anyways, I have a big test Monday and am stumped on something.

I understand that the domain of a function is any number that would make the function impossible to solve. For example, f(x)= 10-(x-4). The domain of the function would be all real numbers except for 6, as plugging 6 for an x value would make the function 0, or impossible. Now I don't understand the "range" of the function at all. I've read the book a number of times and still don't understand as it only states, "The y-values set". If anyone could enlighten me on the concept of the range of a function I would most greatly appreciate it!

Thanks a bunch!
Matt
Whosa jigga wha...reading that makes me wonder how I ever understood that stuff in high school!!!
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Old 10-16-2005, 01:55 PM   #4
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Quote:
Originally Posted by RCHavok797
The domain of the above function is all real numbers and the range is all real numbers.

Isnt the range....all real numbers EXCEPT 14 since the function can not equal 0?


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Old 10-16-2005, 02:05 PM   #5
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A function can equal 0.
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Old 10-16-2005, 02:23 PM   #6
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You're thinking of division. f(x)= 2/X^2 where domain= All Real except 0 because 2/0 is undefined.
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