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06-21-2007, 07:47 AM
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#1
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Registered User
Join Date: Jul 2006
Location: Wherever the army sends me
Posts: 113
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The surface area A of a cube with side s is given by
A = 6s^2
a. Find the surface area of a cube with sides of 3 in.
b. Solve for s^2
(by the way, ^2 means to the power of 2.)
If the sides are 3 in. then s^2 is 3^2 which = 9 which would make A = 54 in^2.
Is that right? I hate math.
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06-21-2007, 07:54 AM
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#2
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Join a 4x4 Club
Join Date: Jan 2005
Location: Albuquerque, NM
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This is a trick question, right? Because a cube's size changes as it melts in the scotch.
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06-21-2007, 07:57 AM
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#3
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Registered User
Join Date: Jul 2006
Location: Wherever the army sends me
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 No this isn't a trick question. I'm taking an online math course and I can't think straight right now. Too much math fries the brain. 
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06-21-2007, 07:58 AM
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#4
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Registered User
Join Date: Aug 2005
Location: Spring Mills, PA
Posts: 121
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It looks right
Don stop watering down your scotch and just used chilled glasses.
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06-21-2007, 07:58 AM
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#5
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Registered User
Join Date: Jan 2003
Location: US and A!!
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54 is correct!
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06-21-2007, 08:48 AM
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#6
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Registered User
Join Date: Jan 2007
Location: NC
Posts: 16
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54 is correct for question a and if I understand part b correctly it's s^2=A/6
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06-21-2007, 09:03 AM
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#7
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Grand Poobah
Join Date: Sep 2006
Location: Cumming GA
Posts: 3,303
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are you sure the answer isn't pi?
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06-21-2007, 09:09 AM
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#8
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Registered User
Join Date: Feb 2006
Location: USA
Posts: 1,112
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Quote:
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Originally Posted by ionakana
are you sure the answer isn't pi?
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that and letter c in a multiple choice question is always the answer
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06-21-2007, 09:10 AM
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#9
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Registered User
Join Date: Feb 2005
Location: ohio
Posts: 107
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its 54 in^2 because its surface area... don't forget the units.
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06-21-2007, 09:44 AM
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#10
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Registered User
Join Date: Jun 2005
Location: College Station, Texas
Posts: 316
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the correct answer is pi over 2 
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06-21-2007, 09:48 AM
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#11
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Registered User
Join Date: Mar 2007
Location: Columbia, SC
Posts: 1,352
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JFK
thats my final answer
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06-29-2007, 07:52 AM
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#12
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Registered User
Join Date: Jul 2006
Location: Wherever the army sends me
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New question...
where ^2 is to the power of 2, ^3 is to the power of 3, etc. etc.
m^4 + 8m^3 + 8m^2 + 64m Factor completely.
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06-29-2007, 08:38 AM
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#13
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Tarpitz
Join Date: Jan 2007
Location: Ventura, Carp, La Conchita, CA
Posts: 959
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Quote:
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Originally Posted by jeep-n00b
New question...
where ^2 is to the power of 2, ^3 is to the power of 3, etc. etc.
m^4 + 8m^3 + 8m^2 + 64m Factor completely.
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how are you going to learn if you have somebody else do the work?
(m^3+8m)(m+8)
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06-29-2007, 08:44 AM
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#14
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Registered User
Join Date: Mar 2005
Location: B'ham, AL
Posts: 827
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Here. http://www.webmath.com/index2.html
This web site will let you plug in equations, solve them and tell you why and how they were solved.
Just click on the link under the topic that you are working on and it will take you to the equation page.
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Quote:
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Originally Posted by ftdranger
You guys on the CJ tech page are a little to tech for me. Must be the leaf springs.
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06-29-2007, 08:45 AM
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#15
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Registered User
Join Date: Jul 2006
Location: Wherever the army sends me
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Quote:
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Originally Posted by skullver
how are you going to learn if you have somebody else do the work?
(m^3+8m)(m+8)
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I was hoping you'd show me the steps. I'm not looking for just the answer. I will need to be able to do this on my final exam.
wouldn't that answer be able to factor down to
m(m^2 + 8)(m + 8)
That's the answer I came up with, but I am not sure. I don't have the warm fuzzy. I didn't do so good on my midterm, and I really need to make it up by acing the rest of the course.
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>
Math Gurus
